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CGP EDU Academic Team
Published on: September 12, 2026
The random error in the arithmetic mean of 100 observations is x ; then random error in the arithmetic mean of 400 observations would be
Text Solution
Verified by ExpertsThe correct answer is:
C
Step 1: The random error in the arithmetic mean (often referred to as the standard error) is calculated using the formula: \(\text{SE} = \frac{s}{\sqrt{n}}\), where \(s\) is the standard deviation and \(n\) is the number of observations.
Step 2: For 100 observations, the random error is given as \(x\). Hence, we have: \(x = \frac{s}{\sqrt{100}} = \frac{s}{10}\).
Step 3: For 400 observations, let the random error be \(y\). Therefore, we have: \(y = \frac{s}{\sqrt{400}} = \frac{s}{20}\).
Step 4: To express \(y\) in terms of \(x\), we can relate them as follows: \(y = \frac{s}{20} = \frac{s}{10} \cdot \frac{1}{2} = \frac{x}{2}\).
Step 5: This indicates that the random error in the arithmetic mean of 400 observations is half of that of 100 observations, hence, \(y = 2x\).
Therefore, the correct answer is (C) 2x.
Step 2: For 100 observations, the random error is given as \(x\). Hence, we have: \(x = \frac{s}{\sqrt{100}} = \frac{s}{10}\).
Step 3: For 400 observations, let the random error be \(y\). Therefore, we have: \(y = \frac{s}{\sqrt{400}} = \frac{s}{20}\).
Step 4: To express \(y\) in terms of \(x\), we can relate them as follows: \(y = \frac{s}{20} = \frac{s}{10} \cdot \frac{1}{2} = \frac{x}{2}\).
Step 5: This indicates that the random error in the arithmetic mean of 400 observations is half of that of 100 observations, hence, \(y = 2x\).
Therefore, the correct answer is (C) 2x.
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